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lianna [129]
3 years ago
6

A bag has ten marbles in it.Three of them are green one of them is red four of them are yellow and two of them are blue.If one m

arble is taken out of the bag randomly what is the probability that it will neither be green nor yellow?
A 0.40
B 0.30
C 0.30 or 0.40
D 0.70
Mathematics
2 answers:
yanalaym [24]3 years ago
7 0
Since there’s 3 green and 4 yellow that adds up to 7 and with only 3 marbles left that is 3:10 and that make the probability 30% or 0.30
Dmitry [639]3 years ago
7 0

Answer:

B is correct.

Step-by-step explanation:

3+4=7

10-7 is the probability of neither Green or Yellow, so 10-7=3.

3/10 is 0.30 in decimal notation, so b is correct.

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P(Y=r) = 4Cr (5/9)^r (4/9)^{4-r},r=0,1,2,3,4

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Given that a bag contains 1 red, 3 green, and 5 yellow balls. A sample of four balls is picked, with replacement

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Thus given y=2 will not affect the pdf of G

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