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stich3 [128]
3 years ago
15

What are the solutions to y=10x2+29x−21

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

x 2 +(29/10)x-(21/10) = 0 Add 21/10 to both side of the equation : x 2 +(29/10)x = 21/10 Now the clever bit: Take the coefficient of x , which is 29/10 , divide by two, giving 29/20 , and finally square it giving 841/400 Add 841/400 to both sides of the equation

Step-by-step explanation:

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Ayako and Joshua have a total of 59 sweets between them.
andreyandreev [35.5K]
A+j=59 so j=59-a

and j=a-3

j=j so

59-a=a-3  subtract a from both sides

59-2a=-3  subtract 59 from both sides

-2a=-62  divide both sides by -2

a=31

n=a=31

Ayako has 31 sweets.
4 0
3 years ago
Is (-5,6) a solution for 4x + 3y = 9
ozzi

Answer:

No.

Step-by-step explanation:

Insert the x and y, (-5 is x and 6 is y) into the equation. It should look like 4(-5)+3(6)=9. 4(-5)=-20 and 3(6)=18. -20+18=2 not 9.

(hope this helps :P)

5 0
4 years ago
Read 2 more answers
(x - 3)2<br> k.<br> + 2x - 4 for x = 5
UNO [17]

Answer:

4k + 6

Step-by-step explanation:

3 0
4 years ago
Anyone know what the answer is???(sorry if it’s unclear)
Sergio [31]

The laws of exponents I will be using are:

(x^y)^z = x^{yz}, and x^y \cdot x^z = x^{y+z}.

For the first part, (15^3)^3 \cdot 15^{-6} = 15^9 \cdot 15^{-6} = 15^3.

For the second part, 15 \cdot (15^3)^2 \cdot (15^{-5})^2 = 15 \cdot (15^6) \cdot (15^{-10}) = 15^{1+6-10} = 15^{-3} = \frac{1}{15^3}.

5 0
3 years ago
How many students text during class? A student created an anonymous survey asking students whether or not they text in class. Of
Misha Larkins [42]

Answer:

1 quantitative

2 32 responded yes, 18 responded no

3 margin error 32%{n}

4 error of students on their phone / not

5 18/-/50

6 16%

7 2%

Step-by-step explanation:

a 95% confidence interval with a 4 percent margin of error means that your statistic will be within 4 percentage points of the real population value 95% of the time.

The margin of error tells you the range of values above and below a confidence interval.

8 0
3 years ago
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