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3 years ago

A coin is flipped 150 times. The results of the experiment are shown in the following table:

1 answer:

8 0

The answer is C because theoretically it should have a 50% of landing heads but instead it lands heads 56% of the time. Thus this is 6% higher than 50%. It's not D because there is not specified detail of how the person got this data so you can assume that the person did a fair survey/data collection.

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(2x-7)-(4x^2+6x-3)+(x^2+4)

masha68 [24]

Answer:

$-3x^2-4x$

Step-by-step explanation:

Simplify:

$\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)$

$=2x-7-\left(4x^2+6x-3\right)+x^2+4$

Group same factor:

$=-\left(4x^2+6x-3\right)+x^2+2x-7+4$

Add :

$=-\left(4x^2+6x-3\right)+x^2+2x-3$

Apply the distributive law: -(a+b) = -a - b

$-\left(4x^2+6x-3\right)=-4x^2-6x+3$

$=-4x^2-6x+3+x^2+2x-3$

Group same factor:

$=-4x^2+x^2-6x+2x+3-3$

Subtract:

$=-4x^2+x^2-6x+2x$

Add:

$=-3x^2-6x+2x$

Group same factor:

$=-3x^2-4x$

Hence answer = $-3x^2-4x$

~lenvy~

8 0

1 year ago

Find the slope of the line that passes through (-2,1) (7,1)

stich3 [128]

Answer:

Step-by-step explanation:

To find the slope of a line, we uses y2-y1/x2-x1:

y2-y1/x2-x1

1-1/7+2

0/9

The slope of the line is 0.

If u have any questions about what I did feel free to ask in the comments!

3 0

2 years ago

Read 2 more answers

A researcher computes the definitional formula for SS, and finds that Σ(x − M) = 44. If this is a sample of 12 scores, then what

olga_2 [115]

Answer:

Option B.

Step-by-step explanation:

Given information:

Σ(x − M) = 44

where, M is mean.

Sample size = 12

The computational formula for sample variance is

$s^2=\dfrac{\sum (x-M)^2}{N-1}$

where, M is sample mean and N is sample size.

Substitute Σ(x − M) = 44 and N=12 in the above formula.

$s^2=\dfrac{44}{12-1}$

$s^2=\dfrac{44}{11}$

$s^2=4.0$

The sample variance is 4.0.

Therefore, the correct option is B.

5 0

2 years ago

Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Sever21 [200]

$\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta$

$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

$\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}$

$\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}$

$\beta$ lies in quadrant I, so $\sin\beta>0$ and

$\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}$

So

$\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}$

8 0

3 years ago

Arrange the numbers in increasing order. -3, +8, -4, +1, -7

Bad White [126]

Answer:

-7,-4,-3,+1,+8

Step-by-step explanation:

The bigger the negative number, the less it's worth

3 0

2 years ago

Read 2 more answers