Answer:
The program code is completed below
Explanation:
Program Code:
"""
Your Name
Course Name, Section (example: ENTD200 B002 Spr15)
Instructor name
Week #
Date completed
"""
months = ["January ", "February", "March", "April", "May", "June", "July"
, "August", "September", "October", "November", "December"]
for i in range(0,12):
print("Month",i+1, "is" , months[i])
Answer:
<em><u>use</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ope</u></em><em><u>ning</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>cl</u></em><em><u>osing</u></em><em><u> </u></em><em><u>tags</u></em><em><u> </u></em>
<em><u>[</u></em><em><u>Tex]</u></em><em><u> </u></em><em><u>[</u></em><em><u>\</u></em><em><u>t</u></em><em><u>e</u></em><em><u>x</u></em><em><u>]</u></em><em><u> </u></em><em><u>ok</u></em>
Answer:
Code is given below and output is attached as an image.
Explanation:
#include <iostream>
#include <fstream>
using namespace std;
bool isPalindrome(int n)
{
// Find reverse of n
int rev = 0;
for (int i = n; i > 0; i /= 10)
rev = rev * 10 + i % 10;
// If n and rev are same,then n is a palindrome
return (n == rev);
}
int main()
{
int min = 1; // Lower Bound
int max = 200; // Upper Bound
ofstream myfile;
myfile.open("palindrome.txt");
for (int i = min + 1; i < max; i++)
if (isPalindrome(i))
myfile << i << endl;
myfile.close();
return 0;
}
Get a program for this perpose or perhaps get a new computer