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Ainat [17]
3 years ago
7

How would you solve (ab)^2 if a=6 and B= -2

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0
(6*-2)^2 my dude. dd s
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In a bag are 5 oranges and 4 mangoes select one replaces it and select another . What is the probability that both selections we
Serggg [28]

Answer:

P(orange)x P(orange)= 5/9 x 5/9= 25/81

Step-by-step explanation:

4 0
4 years ago
Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16
HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image  PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

|A'B'|=k\times |AB|   .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}

PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}

It is noticed that the size of side in preimage is 2\sqrt{13} and the size of same side in image is \sqrt{13}.

Using equation (1), we get

\sqrt{13}=k \times 2\sqrt{13}

k=\frac{1}{2}

k=0.5

Hence, the value of scale factor is 0.5.

7 0
3 years ago
Read 2 more answers
Combine the like to simplify the expression: -5y + 12 + 8y − 6 − 2 =
ANTONII [103]

First, let's move combine like terms:

-5y + 8y = 6 + 2 -12.

3y = -4.

y = -4/3

8 0
4 years ago
Read 2 more answers
Can someone one help you will get that crown on you thing if it right
levacccp [35]

Answer:

False

Step-by-step explanation:

6 0
4 years ago
Find the exact value of secθ if cscθ=-4/3 and the terminal side of θ lies in Quadrant III.
Anton [14]
Quadrant is III so, sign would be negative for Sec.
Now, we know, csc = H / P
So, H = 4, P = 3
Calculate for B, 
B² = H² - P²
B² = 4² - 3²
B² = 16 - 9
B = √7

We know, sec Ф = H / B = 4 / √7
We can write it as: -4√7 / 7  [ -ve sign for 3rd quadrant ]

In short, Your Answer would be Option B

Hope this helps!
6 0
4 years ago
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