If the area of the triangle is 48 square units, what is the total area of sections 1 and 2?
1 answer:
Answer:
48 square unit
Step-by-step explanation:
For a rectangle, area is given by
A=bh
Where b is base and h is height as shown in the attached diagram
For a triangle, area is given by
A∆=½bh
Given that ½bh=48
Then bh=2*48=96 square units
The overall area is 96 square units.
The area for 1&2 combined will be given by deducting the area of triangle from the overall area
Area is 96-48=48 square units
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Start with the parent function f(x) = x³
Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.
Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate
Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x) is translated five units up
So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.
Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.
Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate
Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x) is translated five units up
So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.