First you bring the 9 over with the seven
![-2= \sqrt[3]{x+9}](https://tex.z-dn.net/?f=-2%3D%20%5Csqrt%5B3%5D%7Bx%2B9%7D%20)
Now cube both sides
Finally subtract 9 over and get
Check
![7=9+ \sqrt[3]{-17+9}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-17%2B9%7D%20)
![7=9+ \sqrt[3]{-8}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-8%7D%20)
7=7
Now cube both sides
Finally subtract 9 over and get
Check
7=7
Use five 5s, all four operations, and parentheses to make 25
1 answer:
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Answer:
The area of the irregular figure is 366 cm sq.
Step-by-step explanation:
This irregular figure is made of 1 Rectangle + 1 right Triangle
<u>Area of the Rectangle:</u>
Length of the rectangle = 21 cm,
Width of the rectangle = 14 cm
AREA of Rectangle = LENGTH x WIDTH
= 21 cm x 14 cm = 294 sq cm
⇒Area of the Rectangle = 294 sq cm ..... (1)
<u>Area of the Right Triangle:</u>
Base of the rectangle = 16 cm,
Height of the rectangle = 21 cm - 12 cm = 9 cm
AREA of Right Triangle =
⇒Area of the Right Triangle = 72 sq cm ..... (2)
Now, area of the irregular figure = Area of the( Rectangle +Right Triangle)
= 294 sq cm + 72 sq cm = 366 cm sq
Hence, the area of the irregular figure is 366 cm sq.
For this case we have to by definition:
1 kg equals 1000 grams
Shark 1:
405 kg and 68 grams
Thus, shark 1 weighs 405,068 grams.
Shark 2:
324 kg and 75 grams
Thus, shark 2 weighs 324,075 grams.
Subtracting we have:
Thus, shark 1 weighs 80,993 grams more than the second.
Answer:
Shark 1 weighs 80,993 grams more than the second.