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3 years ago

Solve 1/4 divided by 3

2 answers:

6 0

The anwser is 0.083 a bunch of threes follow but the aren't important all you need to do is round which that should be rounded enough.

Musya8 [376]3 years ago

3 0

1/4 : 3 =

1/4 * 1/3 =

1/12

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(Y^2-3y^3-2+5y)-(7+8y^2-4y^2+6y^3

miv72 [106K]

Answer:

The answer to your question is: -9y³ - 3y² + 5y - 9

Step-by-step explanation:

( y² - 3y³ - 2 + 5y ) - (7 + 8y² - 4y² + 6y³)

y² - 3y³ - 2 + 5y - 7 - 8y² + 4y² - 6y³

Like terms -3y³ - 6y³ + y² - 8y² + 4y² + 5y - 2 - 7

-9y³ - 3y² + 5y - 9

8 0

3 years ago

The sides of a square field are 12 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co

loris [4]

Area of the square is 144m.
Area of the circle is 113.1m.
Subtract A of circle from A of Square which equals 30.9meters. That is your answer.

If you want I can teach you step by step just comment if you want me to...

8 0

3 years ago

Solve this please! Also fill in the blanks

Annette [7]

X, 14, 2x - 16 is greater than or equal to 12, 12, add 16 to both sides, divide both sides by 2, x is greater than or equal to 14. each box filled in is represented by the commas in between each phrase. I don’t know the rest but I did get the first part.

4 0

3 years ago

HELP PRECALC NEED IN PROOF FORM

Vinil7 [7]

Hello, please consider the following.

We know the following, right ?

$(\forall a, b \in \mathbb{R}) \left( sin(a+b)=sin(a)sin(b)+cos(a)cos(b) \right)$

So, here, it gives.

$Asin(\omega t+\phi)=Asin(\phi){\sf \bf sin(\omega t)}+Acos(\phi){\sf \bf cos(\omega t)}\\\\=c_2{\sf \bf sin(\omega t)}+c_1{\sf \bf cos(\omega t)}\\\\\text{ *** where }c_2=Asin(\phi) \text{ and } c_1=Acos(\phi) \text{ ***}$

Do not hesitate if you need further explanation.

5 0

4 years ago

3 cups a b c contain only salt and water the different mixtures are a salt:water 3:22 b Salt 1/8 c salt 12.75% what cup has the

ddd [48]

Answer:

Cup A

Step-by-step explanation:

Cup A

Salt: Water = 3:22

Expressed as a percentage

$\dfrac{3}{22} \times 100 = 13.6\%$

Proportion of Salt =13.6%

Cup B

Salt: Water = 1:8

Expressed as a percentage

$\dfrac{1}{8} \times 100 = 12.5\%$

Proportion of Salt =12.5%

Cup C

Proportion of Salt = 12.75%

Therefore, Cup A has the greatest proportion of salt.

7 0

3 years ago