Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
Answer:
B = 34.2°
C = 58.2° or 121.8°
c= 10.6
Step-by-step explanation:
Step 1
Finding c
We calculate c using Pythagoras Theorem
c²= a² + b²
c = √a² + b²
a= 8, b = 7
c = √8² + 7²
c = √64 + 49
c = √(113)
c = 10.630145813
Approximately c = 10.6
Step 2
Find B
We solve this using Sine rule
a/sin A = b/sin B
A = 40°
a = 8
b = 7
Hence,
8/sin 40° = 7/sin B
8 × sin B = sin 40° × 7
sin B = sin 40° × 7/8
B = arc sin (sin 40° × 7/8)
B ≈34.22465°
Approximately = 34.2°
Step 3
We find C
Find B
We solve this using Sine rule
b/sin B = c/sin C
B = 34.2°
b = 7
c = 10.6
C = ?
Hence,
7/sin 34.2° = 10.6/sin C
7 × sin C = sin 34.2 × 10.6
sin C = sin 34.2° × 10.6/7
C = arc sin (sin 34.2° × 10.6/7)
C = arcsin(0.85)
C= 58.211669383
Approximately C = 58.2°
Or = 180 - 58.2
C = 121.8°
So our two equations are y=-8x-4 and y=-16, and since in both equations, something equals the same y, those two are the same. So we can combine the two into -16=-8x-4. In the question, they are asking to solve for x. So to do that, you need to isolate your variable. Now for solving algebraic equations, you use reverse PEMDAS (SADMEP), meaning you add 4 to both sides to clear the -4 one the rights side to get -12=-8x. Then you divide both sides by -8 to get 12/8, which simplifies to 3/2.
Answer:
i think the answer is 19x^-2x+2
Answer:
m<R ≈ 22.62°
Step-by-step explanation:
Reference angle = R
Side opposite to R = 5 cm
Adjacent side length = 12 cm
Thus, applying TOA, we have:
Tan R = opp/adj
Tan R = 5/12
R = tan^{-1}(5/12)
R ≈ 22.62° (nearest hundredth)
