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Nadusha1986 [10]
3 years ago
14

Name one combination of 12 coins

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

11 pennies and 1 nickel

Step-by-step explanation:

11 pennies and 1 nickel is a combination of 12 coins.

-> If there is more context, please include it.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Estimate the value 9.03 + 19.87 x 3.11 - 4.97
Nuetrik [128]

Answer:

-53.754

Step-by-step explanation:

<u>step 1:</u>

9.03 + 19.87 = 28.9

<u>step 2:</u>

3.11 - 4.97 = -1.86

<u>step 3:</u>

28.9 x -1.86 = -53.754

3 0
3 years ago
Find the missing y-coordinate that makes the two triangles congruent. Triangle ABC: A(8,4), B(2,6), C(5, 0) Triangle MNO: M(7,4)
Zolol [24]

Answer:

y = 8

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides and three angles of both triangles are equal.

The distance between two points on the coordinate plane is given as:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

In triangle ABC:

|AB|=\sqrt{(2-8)^2+(6-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|AC|=\sqrt{(5-8)^2+(0-4)^2}=5\\\\|BC|=\sqrt{(5-2)^2+(0-6)^2    }=\sqrt{45}

In triangle MNO:

|MN|=\sqrt{(1-7)^2+(2-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|MO|=\sqrt{(4-7)^2+(y-4)^2}\\\\|NO|=\sqrt{(4-1)^2+(y-2)^2    }

Since triangle ABC and triangle MNO are congruent, hence:

|AB| = |MN| = 2√10, |AC| = |MO| = 5, |BC| = |NO| = √45

|AC|=|MO|=5\\\\\sqrt{(4-7)^2+(y-4)^2}=5\\\\(4-7)^2+(y-4)^2=25\\\\9 +(y-4)^2=25\\\\(y-4)^2=16\\\\square\ root\ of\ both\ sides:\\\\y-4=4\\\\y=4+4\\\\y=8

Hence O = (4, 8)

3 0
3 years ago
Help me out please!!!
AleksAgata [21]
1) side BD is common

2) angle ABD is equal to angle BDC (alternate angles)

3) angle CBD is equal to angle ADB (alternate angles)
5 0
3 years ago
Let X have the probability mass function P(X = −1) = 1 2 , P(X = 0) = 1 3 , P(X = 1) = 1 6 Calculate E(|X|) using the approaches
Studentka2010 [4]

Answer:

Step-by-step explanation:

From the given information:

Note that the possible values of Y are 0 and 1 because;

y = 0 if X = 0 and y = 1 if X = ±1

∴

P(Y =0) = P(X = 0) =\dfrac{1}{3}

P(Y = 1) = P(X = -1  \ or \ 1) \\ \\ = P(X = -1) + P(X = 1)

= \dfrac{1}{2}+ \dfrac{1}{6}

=\dfrac{3+1}{6}

= \dfrac{2}{3}

b)

E(|X|) = \sum |x| P(X=x) = ( 1 \times \dfrac{1}{2}) + ( 0\times \dfrac{1}{3}) + ( 1 \times \dfrac{1}{6})

= \dfrac{2}{3}

7 0
3 years ago
Find the unknown angle in each case.
antiseptic1488 [7]
A = 50
For the other one it is 100
If you are looking for z then z is 55
4 0
3 years ago
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