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arsen [322]
4 years ago
7

Plz help it’s du in like 1 hour

Mathematics
1 answer:
Zinaida [17]4 years ago
5 0
FIRST METHOD
From the frequency table, X stands for the number and F stands for the number of time that a particular number occur.
So, if we break the table down, we are going to have the following numbers:
1, 1, 2, 2, 3, 3, 3, 3, 3, 4.
The total number of occurrence =  Addition of F = 10
Mean = [Summation of all occurrence] / Number of occurrence
Mean = [1+1+2+ 2+3 +3 +3 +3 +3 + 4] / 10 = 25 /10 = 2.5
Therefore, mean = 2.5

SECOND METHOD
Mean = [ 1*2] + [2* 2] + [3 * 5] + [4*1] / [2+ 2 + 5+ 1]
Mean = 2 + 4 + 15 + 4 / 10 = 25 / 10 2.5
Therefore, Mean = 2.5
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Find all solutions for a triangle with A=140, b=10, and a=3. Round to the nearest tenth.
grandymaker [24]

I can try to answer this to the best of my knowledge

so if angle A is 140 degrees) then the other two angles *together* add up to 40 degrees)

so both B and C are less than 40.

 that means their sides are less than the side opposite angle A

, so less than 3. But they tell you b is 10. hope it helps

4 0
3 years ago
Read 2 more answers
Round to the nearest tenth
Semmy [17]

Answer:

60 degrees

Step-by-step explanation:

I believe in the triangle it says 57 degrees so if you round 57 to the nearest tenth you get 60 so it would be 60 degrees

4 0
3 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
REY [17]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

5 0
3 years ago
Read 2 more answers
take 25% off the original. now take off an additional 10% and calculate the new sales cost of this item. what is your total perc
Aneli [31]

x = original price, or 100%

if we take off 25% from 100% what's left is 75%, that's the discounted price.

let's then take 10% of that.

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{75\% of "x"}}{\left( \cfrac{75}{100} \right)x\implies 0.75x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{10\% of 0.75x}}{\left( \cfrac{10}{100} \right)0.75x\implies 0.075x}~\hfill \stackrel{\textit{total percent savings}}{0.75x-0.075x\implies 0.675x} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{changing that to percent format}}{0.675\cdot 100\implies 67.5\%}

8 0
3 years ago
PLEASE HELP?
lukranit [14]
Number of ones = 60
Number of twos = 62
Number of threes = 59
Number of fours = 64
Number of fives = 63
Number of sixes = 75

Total even outcomes = total number of two, four and sixes = 62 + 64 + 75 = 201

Total outcomes = 60+62+59+64+63+75= 383

Probability if rolling an even number = 201/383

percentage= 201/383 × 100 = 52.48% ~ 52.5%

\boxed{\text{\huge{\red{Answer: D}}}}

5 0
3 years ago
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