Question

one term of an arithmetic sequence is a17=82 and d=-6. write a rule for the nth term of the sequence. then find a10

Answer 1

Answer:

$a_{10}=124$

Step-by-step explanation:

In an arithmetic sequence, we are given that:

$a_{17}=82\\d=-6$

The nth term of an arithmetic sequence, $a_n=a+(n-1)d$

When n=17, $a_{17}=82,d=-6$, we have:

$a_{17}=a+(17-1)(-6)$

82=a+(16)(-6)

82=a-96

a=82+96

a=178

Therefore, the 10th term of the sequence

$a_{10}=178+(10-1)(-6)\\=178+9(-6)\\=178-54\\a_{10}=124$