Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
x= 13.5
Step-by-step explanation:
f(x) = 2x + 9
f(x) = 36
Set the 2 equations equal to each other;
2x + 9 = 36
Subtract 9 from both sides;
2x = 27
Divide both sides by 2;
x = 13.5
<em>Check:</em>
f(x) = 2x + 9
f(13.5) = 2(13.5) + 9= 27 + 9 = 36
q = 10p because all of them are multiplied by ten
29.98/24≈1.25
2.29-1.25= $1.04
