Multiply (3b 2+ 4b + 8)(-2b 2+ b + 10).

1 answer:

4 0

Answer: -30b^2+76b+80
Explanation:
Multiply the second parenthesis by each term from the first parenthesis:
3b•2(-2•2+b+10)+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then distribute 3b•2 through the parenthesis
-24b^2+6b^2+60b+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then collect like terms
-30b^2+60b+40b-32b+8b+80
Collect like terms=
-30b+76b+80

You might be interested in

Help me...............

True [87]

Answer:

Brainliestgive o020201000

3 0

3 years ago

Whoever helps with number 5 gets brainliest answer and 10 points :)

nata0808 [166]

Count:5Sum:341Mean:68.2Median:62Mode:48, 40, 93, 62, 98

6 0

3 years ago

Read 2 more answers

HELP!!!!<br> Please help me!!<br> I need help!!<br> HELP!!!!

mote1985 [20]

Answer:

Pretty sure it's A

Step-by-step explanation:

The x outside the parenthesis means that there's an x intercept at (0,0) and (x-3) means there's another one at (3,0)

5 0

3 years ago

Please help me on number 3

Mars2501 [29]

circle=360°

360÷10=36

36÷3=12

Answer is 12

4 0

3 years ago

Which expression is equivalent to sqrt2/^3sqrt2

zimovet [89]

The given expression is $\frac{\sqrt{2}}{\sqrt[3]{2}}$

This can be simplified using the radical properties as below

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\$

Now using exponent properties we can write

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\$

7 0

3 years ago

Read 2 more answers

Multiply (3b​ 2​+ 4​b​ + 8)(-2​b​ 2​+ ​b​ + 10).

Multiply (3b 2+ 4b + 8)(-2b 2+ b + 10).