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olga_2 [115]
3 years ago
13

PLEASE ANSWER ASAP, 25 points if you answer and will get brainliest if you show all work. <br /><br />If you drive a

t x miles per hour and apply your breaks, your stopping distance in feet is approximately <br />f(x) = x + \frac{ {x}^{2} }{20}<br />a)By how much will your stopping distance increase if you increase your speed from 20 mi/h to 30 mi/h?<br />b)By how much will your stopping distance increase if you increase your speed from 50 mi/h to 60 mi/h? <br />c)An important driving guideline is that you leave one car length between your car and the car in front of you for every 10 mi/h of speed. Thus, you should leave three car lengths if you are driving at 30 mi/h and 5 car lengths if you are driving at 50 mi/h. Is this guideline consistent with the model f(x)?
Mathematics
1 answer:
amm18123 years ago
6 0
Answer is x{f2}=x^25
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Step-by-step explanation:

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3 years ago
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The equation y=750x represents the number of dollars y Olivia earns in x weeks. Determine if there is a constant of variation. I
Klio2033 [76]

Answer:

<h3>There is a constant of variation in the equation and it is 750. This means that the amount olivia earns increases by $750 every week.</h3>

Step-by-step explanation:

Given the equation y = 750x which represents the number of dollars y Olivia earns in x weeks, from the equation, it can be inferred that the number of dollars olivia earns is DIRECTLY PROPORTIONAL to the number of weeks. This relationship is therefore a direct variation.

In direct variation, increase in a variable will lead to corresponding increase in the other variable and vice versa by a factor known as the constant of variation.

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comparing the general expression above with the equation in question,

y = 750x

k = 750

Therefore we can conclude that there is a constant of variation in the equation and it is 750. This means that the amount olivia earns increases by $750 every week.

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4 years ago
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