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olga_2 [115]
3 years ago
13

PLEASE ANSWER ASAP, 25 points if you answer and will get brainliest if you show all work. <br /><br />If you drive a

t x miles per hour and apply your breaks, your stopping distance in feet is approximately <br />f(x) = x + \frac{ {x}^{2} }{20}<br />a)By how much will your stopping distance increase if you increase your speed from 20 mi/h to 30 mi/h?<br />b)By how much will your stopping distance increase if you increase your speed from 50 mi/h to 60 mi/h? <br />c)An important driving guideline is that you leave one car length between your car and the car in front of you for every 10 mi/h of speed. Thus, you should leave three car lengths if you are driving at 30 mi/h and 5 car lengths if you are driving at 50 mi/h. Is this guideline consistent with the model f(x)?
Mathematics
1 answer:
amm18123 years ago
6 0
Answer is x{f2}=x^25
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Your realized income is $36,864.00/yr. Your fixed and housing expenses are 32% and your savings are 15% of your realized income
andriy [413]

Answer:

You will have $1628.16 per month in discretionary money.

Step-by-step explanation:

In order to find the amount of money you have left for discretionary purposes at the end of the money, you need to calculate the total amount of your monthly pay is going towards expenses and savings.  Since there are 12 months in a year, your monthly income is $3072.  Of that amount, you spend 32% on housing and 15% on savings, for a total of 47%.  The remaining percentage of your income would be considered discretionary, which would account for 53%.  To find the amount of money, you take your monthly income and multiply it by 53%, or .53, which gives you $1628.16.  

6 0
3 years ago
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros for
timama [110]
The general form of a polynomial is: x² + bx + c = 0. Substituting the roots,

3² + b(3) + c = 0
3b + c = -9 --> eqn 1

(5 + √5)² + (5 +√5)(b) + c = 0
(5+√5)b + c = -30-10√5 --> eqn 2

Solving both equations simultaneously by subtracting eqn 2 from eqn 1,
(-2 - √5)b = 21 + 10√5
b = -8 - √5

Using eqn 1,
3(-8 - √5) + c = -9
-24 - 3√5 + c = -9
c = -9 + 24 + 3√5
c = 15 + 3√5

Hence, the polynomial is: <em>f(x) = x² + (-8 - √5)x + (15 + 3√5)</em>.
7 0
4 years ago
Without computing, determine which number is greater, [(-4)^4]^5 or -[(4^12)^3 Explain your reasoning.
Strike441 [17]

Answer:

I think [(-4)^4]^5, but I'm not completely sure

Step-by-step explanation:

1.0995116e+12 greater than -4.7223665e+21

[(-4)^4]^5=1.0995116e+12

-[(4^12)^3=-4.7223665e+21

7 0
3 years ago
100 PTS!! PLEASE HELP! OVER DUE
Reika [66]

Answer:

-\frac{1}{2} \vec {c}

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because \frac{4}{4}=1=\frac{-2}{-2}

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector.  This means that there is some number "k", such that k \vec{c} = \vec {d}, or equivalently, kc_x=d_x and kc_y=d_y.

If kc_x=d_x and kc_y=d_y, we just need to substitute known values and solve for k:

kc_x=d_x\\k(4)=(-2)\\k=\dfrac{-2}{4}\\k=-\frac{1}{2}

Double checking that k works for the y-coordinates as well:

kc_y=d_y

(-\frac{1}{2}) (4)    ?    (-2)

-2=-2 \text{ } \checkmark

So, -\frac{1}{2} \vec {c} = \vec {d}

6 0
2 years ago
Please help. im not good with probability
qaws [65]
2 out of 10 chances

2/10 is 1/5
8 0
3 years ago
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