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krok68 [10]
3 years ago
9

What is the value of 4 1/3÷1/9?Enter your answer as a fraction in simplest form, like this: 3/14

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Hey there!

  • \bold{4\frac{1}{3}\times\frac{1}{9}}
  • \bold{4\frac{1}{3}=\frac{13}{3}}
  • \bold{\frac{13}{3}(\frac{1}{9})}
  • \bold{13\times1=13}
  • \bold{9\times3=27}
  • \boxed{\boxed{\bold{Answer:\frac{13}{27} }}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

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How many tens are in 120,000
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12000
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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Help me please and explain. <br><br>FIND THE AREA OF THE UNSHADED REGION ​
bagirrra123 [75]

To solve this first find the area of each of the white shapes inside the rectangle

The formula for the area of a circle is:

A = πr²

In this case we know that the radius is 2

Plug what you know into the area of a circle formula:

A = π2²

A = π4

A = 4π

A ≈ 12.57

The formula for the area of a square is:

A = Length x Height

In this case we know that both length and height are 3

Plug what you know into the formula for area of a square:

A = 3 x 3

A = 9

To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):

12.57 + 9 ≈ 21.57

To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.

The formula for the area of a rectangle is:

A = Length x Height

The length is 10 and the height is 7

A = 10 x 7

A = 70

Shaded region:

70 - 21.57 = 48.43

Unshaded region: 21.57

Total area of surrounding rectangle: 70

Shaded region: 48.43

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
3 years ago
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Iana started to evaluate the function f(x) = 2x2 – 3x + 7 for the input value 2.
Sati [7]
The answer is nine because 2(4)=8   3(2)=6   7=7, os 8-6+7= 2+7 =9
5 0
3 years ago
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