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Kisachek [45]
3 years ago
7

Which of the following number odd​

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0
The odd numbers are 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31 and so on
frosja888 [35]3 years ago
6 0
Any number that is not divisible by 2
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What are the domain and range of the function f(x) = 3x 5?.
Bingel [31]

The domain and range of the given function both are the real numbers.

<h2>Given that:</h2>
  • The domain and range of function f(x) = 3x + 5 has to be found.

<h2>Explanation for domain and range:</h2>

Considering working in real numbers, domain is \mathbb{R} and range is \mathbb{R} too.

Domain can be complex numbers too, but for the sake of daily life cases, we consider working in real numbers.

Thinking of it as equation of straight line can help.

The given function is monotonically increasing and continuous.

Thus Range can be calculated as  interval ( f(min value of domain), f(max value of domain) ) which gives us \mathbb{R} as range.

Below is the plot of f(x) = 3x + 5 in real number plane.

In fact, any linear equation of the form

y = mx + c ;    \: \: c \in R \: and \: m \in {R-\{0\}}

has  both domain and range as real numbers.

For more information, refer to:

brainly.com/question/12208715

7 0
3 years ago
Read 2 more answers
What is the answer to
katovenus [111]

Answer:

y\geq2

Step-by-step explanation:

1. switch sides

2. distribute

3. simply (combine like terms) in this case it would go to 22y

4. add 48 to both sides

5. simplify

6. divide

y\geq2

6 0
4 years ago
Evaluate cos(θ) when θ=3π/2?
Ivanshal [37]

Answer:

0

Step-by-step explanation:

3 0
3 years ago
Solve the following equation.-3 = x/5
Umnica [9.8K]
I hope this helps you




x/5= -3



x= -3.5



x= -15
7 0
4 years ago
Use the equation to answer the following question y=(x-3(x+2)/(x+4)(x-4)(x+2)
givi [52]

Answer:

See below

Step-by-step explanation:

The given rational function is;

y=\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}

The given function is not continuous where the denominator is equal to zero.

(x+4)(x-4)(x+2)=0

The function is discontinuous at x=-4,x=4,x=-2

b) The point at x=-2 is a removable discontinuity(hole) because (x+2) is common to both the numerator and the denominator.

The point at x=-4 and x=4 are  non-removable discontinuities(vertical asymptotes)

c) The equation of the vertical asymptotes are x=-4 and x=4

To find the equation of the horizontal asymptote, we take limit to infinity.

\lim_{x\to \infty}\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}=0

The horizontal asymptote is y=0

8 0
3 years ago
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