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olga55 [171]
4 years ago
6

Which of the following is a monomial?

Mathematics
1 answer:
Dmitrij [34]4 years ago
5 0
"mono" means 1 or single. In algebra, a monomial is any number that is alone or by itself. For this question, among the choices, the monomial is the number 4. Therefore the answer to this question is letter B. 4.
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Find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it.
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π×10^2=314.15

Step-by-step explanation:

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What is the value of M/3=2
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M=3*2

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Step-by-step explanation:

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Hospital records show that a certain surgical procedure takes on an average 111.6 minutes with a standard deviation of 2.8 minut
Arisa [49]

Answer:

At least 37.74% of the procedures takes between 97.6 and 125.6 minutes

Step-by-step explanation:

The percentage is the area of the standard normal distribution curve between the values 97.6 and 125.6

The standard normal variate of the given data is found as

Z=\frac{X-\overline{X}}{\sigma }

Thus for the given values Z is calculated as under

Z_1=\frac{97.6-111.6}{2.8}=-5

Similarly for the other value we have

Z_2=\frac{125.6-111.6}{2.8}=5

Thus the area between the calculated values can be found from standard normal distribution table to be 37.74%

8 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
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