I couldn’t see the whole picture so I’m not sure if I could really help I’m sorry maybe next time
i suppose that t is an exponent. so let: v(t)=final prize of the scooter...t=time in years.....p=initial prize of the scooter . r= rate of depreciation per year so v(t)=p(1-r)^t....
Answer:
40
Step-by-step explanation:
Angle Formed by Tangent and Secant
= 1/2 (DIFFERENCE of Intercepted Arcs)
< WVT = 1/2 ( WT - UW)
3x+4 = 1/2 (( 14x +7) - (7x+11))
Distribute
3x+4 = 1/2 ( 14x +7 - 7x-11)
Combine like terms
3x+4 = 1/2 ( 7x -4 )
Multiply each side by 2
6x +8 = 7x-4
Subtract 6x from each side
+8 = x-4
Add 4 to each side
12 =x
WVT = 3x+4
= 3*12 +4
= 36+4
= 40
Answer:
I think the answer of this question is,
Step-by-step explanation:
The 20th term may be 1048576
Answer:
obtuse
Step-by-step explanation:
The largest angle is more than 90°, so the triangle is called an "obtuse" triangle.
Here are the classifications based on the measure of the largest angle:
< 90° -- acute triangle
= 90° -- right triangle
> 90° -- obtuse triangle . . . . . like the one in this problem statement
