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kirza4 [7]
3 years ago
5

Hii. can you answer pt b? thxx

Mathematics
2 answers:
kiruha [24]3 years ago
7 0

There would be little to no change, due to the fact of there being little change anyway looking at the current plots, and table.

cul stuff

raketka [301]3 years ago
6 0

heres ur brainliest lel

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27%=27/100


so 27/100=81/x


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that the answer

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Service calls arriving at an electric company follow a Poisson distribution with an average arrival rate of 5656 per hour. Find
liberstina [14]

Answer:

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The variance is the same as the mean.

Average rate of 56 calls per hour:

This means that \mu = 56n, in which n is the number of hours.

Find the average and standard deviation of the number of service calls in a 15-minute period.

15 minute is one fourth of a hour, which means that n = \frac{1}{4}. So

\mu = 56n = \frac{56}{4} = 14

The variance is also 14, which means that the standard deviation is \sqrt{14} = 3.74

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

4 0
2 years ago
Points D,E,F are non-Collin war.How many lines can be drawn that pass through F and are perpendicular to DE
Arada [10]
Points def are parallel
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3 years ago
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puteri [66]

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please mark as brainliest  if it helped

6 0
3 years ago
Read 2 more answers
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