Answer: point C and D
Step-by-step explanation:
i am in College so this is the right answer
hope this help
Answer:
Step-by-step explanation:
decimal repeats without a pattern
X2+y2=65............1
X2-3y=37..............2
÷both equation. 1 by 2
X+y=32,5
X=32,5-y......... 3
Sub 3 in 2
(32,5-y)2-3y=37
65-2y-3y=37
65-5y=37
-5y=37-65
-5y= - 28 divide both sides by - 5
Y=5,6........ 4
Sub 4 in 3
x=32,5-y
=32,5-5,6
=26,9
Hope it's the way you wanted it
<span>17=-b+10
Subtract 10 from both sides
7= -b
Divide both sides by -1
Final Answer: -7= b</span>
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
