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a_sh-v [17]
3 years ago
9

Simplify -7(m^3n^4)^2 show work please

Mathematics
1 answer:
Papessa [141]3 years ago
8 0

The only other thing I can see you can do on this is to get rid of the power 2 like below

-7(m^3n^4)^2

Multiply the 3 and the 4 by 2

-7m^6n^8

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What’s the answer????
Brilliant_brown [7]

Answer: 3000 inch

Step-by-step explanation: Volume= l*w*h

15*8*25

5 0
3 years ago
If 0 < x < 1 and 0 < y < 1, which of the following must be true?
katovenus [111]
0<x<1 and 0<y<1

x>0 so x is positive and y>0 so y is also positive.
When you multiply two positive numbers you always get a positive number, so the product of x and y must be positive, or greater than 0.
xy>0 - it must be true
xy<0 - it can't be true
Also when you divide a positive number by a positive number you always get a positive number, so the quotient of x and y must be positive.
x/y<0 - it can't be true
D and E can be true, but don't have to. It depends on the values of x and y. If x>y, then x-y>0 is true and x-y<0 isn't true; if x<y, then x-y>0 isn't true and x-y<0 is true.

Therefore, only A <u>must</u> be true.
3 0
3 years ago
A: 1/2
S_A_V [24]

A= -2

B= Y-1= -1/2 (X-3)

7 0
3 years ago
Read 2 more answers
14.8 = n minus 0.3<br> n = negative 15.1<br> n = negative 14.5<br> n = 14.5<br> n = 15.1
dlinn [17]

Hello!

14.8 = n - 0.3

n - 0.3 = 14.8

n = 14.8 + 0.3

n = 15.1 → value of n

Good luck! :)

4 0
2 years ago
On a standard reticulocyte preparation with new methylene blue, there are 100 cells counted with blue-stained granulofilamentous
DIA [1.3K]

Answer:

0.322 × 10¹² /L

Step-by-step explanation:

Data provided in the question:

Number of cells counted with blue-stained granulofilamentous material

i.e number of RET = 100

The red blood cells count = 3.22 × 10¹² /L

Hematocrit = 30%

Now,

RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%

= [ 100 ÷ 1000 ] × 100%

= 0.1 × 100%

= 10%

also,

Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100

= [ 10 × 3.22 × 10¹² /L ] ÷ 100

= 0.322 × 10¹² /L

8 0
3 years ago
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