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3 years ago

Write an equation in slope-intercept form for the line that satisfies the following condition.

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

Answer:

y = - x + 69

Step-by-step explanation:

Given the following :

Point on graph : (29, 8)

Equation of line ; y= 5x +17.

From the equation slope of line = 5

Intercept = 17

Slope of perpendicular line = - 1/5 ( negative reciprocal)

Using the equation :

y - y1 = m(x - x1)

From the Point given:

x1 = 29, y1 = 8

y - 8 = (- 1/5)(x - 29)

y - 8 = -1/5x + 29/5

y = -1/5x + 29/5 + 8

Multiply through by 5

y = - x + 29 +40

y = - x + 69

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-5x= -15 solve for x

cricket20 [7]

Answer:x=3

Step-by-step explanation:

-5x=-15

divide by -5

x=3

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3 years ago

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If U=pi(r+h),find r when U=16 1/2 and h=2 solve this question by take the value of pi 22/7

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3 years ago

Which expression is equivalent to 3m1-m? A) 2+m-1+m B) 1+m C) 3m-1 D) 3m

valkas [14]

Answer:

Step-by-step explanation:

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3 years ago

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Create an equivalent system of these equations and test your solution x + y = 1 x 3y =9

ad-work [718]

An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides

assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent

ok, solve initial

x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation

-x-y=-1
x-3y=9 +
0x-4y=8

-4y=8
divide both sides by -4
y=-2

sub back
x+y=1
x-2=1
add 2
x=3

x=3
y=-2
(3,-2)

if we test it in other one

2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep

2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep

solution is (3,-2)

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3 years ago

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Im in need of help so please help[ :)))

const2013 [10]

Given:

Consider the pentagon MVEDR is dilated with the origin as the center of dilation using the rule $(x,y)\to(\dfrac{2}{3}x,\dfrac{2}{3}y)$ to create pentagon M'V'E'D'R'.

To find:

The correct statement.

Solution:

If a figure dilated by factor k, then the rule of dilation is

$(x,y)\to (kx,ky)$

Here,

If k>1, then the image is larger than the original figure.

If k<1, then the image is smaller than the original figure.

We have,

$(x,y)\to(\dfrac{2}{3}x,\dfrac{2}{3}y)$

Here, M'V'E'D'R' is image and MVEDR is original figure. The scale factor is

$k=\dfrac{2}{3}$

Pentagon M'V'E'D'R' is smaller than pentagon MVEDR because the scale factor is less than 1.

Therefore, the correct option is B.

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3 years ago