Question

4. plz show ur work

Answer 1

Percent Error =
$( \frac{ |experimental \: value - accepted \: value| }{accepted \: value} ) \times (100)$
So, Ari's experimental value is ,
$\frac{2.49g/ {cm}^{3} + 2.56g/ {cm}^{3} +2.72g/ {cm}^{3} }{3} =2.59g/ {cm}^{3} (average)$
The accepted value is,
$2.65g/ {cm}^{3}$

Here's The Work
$( \frac{ |2.59g/ {cm}^{3} -2.65g/ {cm}^{3} | }{2.65g/ {cm}^{3} } ) \times (100) = 2.26 \: percent \: of \: error$
Ari's Average Measurements Have An Percent Error Of 2.26%