If the radius of mars is about 13.7% of neptune's radius, what is the radius of neptune?

A machine that makes dimes is adjusted to make them at diameter 1.9 cm. Production records show that when the machine is properl

yanalaym [24]

Answer:

0.0772

Step-by-step explanation:

P(Power) + P(Type II Error) = 1, so P(Type II Error) = 1 – P(Power) = 1 – 0.9228 = 0.0772.

8 0

3 years ago

the selling price of a television set is $125 more than twice the cost. find the cost if the selling price is $325.

OverLord2011 [107]

The cost is $100. Take $325, and subtract $125. It gives you $200. And you have to divide that in half cuz the price is twice the cost. So the cost is $100

(* I love getting brainliest! ;) *)

6 0

3 years ago

Read 2 more answers

In a soccer tournament teams receive 6 points for winning a game 3 points for trying a game and 1 point for each goal they score

Alex777 [14]

I beleive it is 6(2) + 3 (1) + 1(5) = 20 points :)

8 0

3 years ago

Find the equation of the line shown.<br> 1<br> 0<br> -2

wolverine [178]

Answer:

your didn't give any proper point ,but i assuming the the question as

the line pass through the point (1,0,-2)

so answer is

(x-1)/a = y/b = (z+2)/c,

where a,b,c are constant

Step-by-step explanation:

4 0

2 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago