6x^3+11x^2-4x-4/3x-2 divide the polynomial

1 answer:

4 0

$\frac{6x^3 + 11x^2 - 4x - 4}{3x - 2} \\ \\ \frac{(6x^2 - x - 2)(x + 2)}{3x - 2} \\ \\ \frac{(6x^2 + 3x - 4x - 2(x + 2)}{3x - 2} \\ \\ \frac{(3x(2x + 1) - 2(2x + 1))(x + 2)}{3x - 2} \\ \\ \frac{(2x + 1)(3x - 2)(x + 2)}{3x - 2} \\ \\ (2x + 1)(x + 2) \\ \\$

The final result is: (2x + 1)(x + 2).

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