Can someone help me

Dimitri is helping to plan the school talent show. Each performer for the talent show has 6 66 minutes for his or her performanc

antoniya [11.8K]

The talent show consists of introduction and talent performance. It could be written into this equation
Talent show duration= introduction + talent performance

Each performer for the talent show has 6 minutes for their show, the <span>introduction of the talent show is 24 minutes, and the total duration should be 150 minutes. Then, maximum performance count of the show would be:
</span>
Talent show duration= introduction + talent performance
<span>150 min = 24 min + (performance count * 6min)
</span>performance count = (150min - 24min) / 6 min
performance count=21

7 0

3 years ago

The bed of a pick up truck measures 4' x 8" to the nearest inch what is the length of the longest thin metal bar that will lie f

Andru [333]

Ok so what y ou want to do it to max space, lie it diagonally
use pythagoren theorem
first convert the units

4'=4 feet
8''=8 inches
convert to inches
4 feet times 12=48 inches

so
pythagorea theorem is
a^2+b^2=c^2
c=hypotonuse
a and b are legs
in a right triangle

8 and 48 are the legs
fidn hypotonuse

8^2+48^2=c^2
64+2304=c^2
2368=c^2
8√37=c
aprox
48.66=c
4 feet amd 0.66 inches

6 0

3 years ago

A student has a savings account earning 3% simple interest. She must pay $1900 for first-semester tuition by September 1 and $19

Anastaziya [24]

Answer:

$3781.19

Step-by-step explanation:

Let us assume that the student has to earn $(1900 + x) by September 1 so that he can pay the $1900 tuition fee by September 1 and the remaining $x will grow at 3% simple interest to make him able to pay another tuition fee of $1900 by January 1.

So, we can write $x( 1 + \frac{4 \times 3}{12 \times 100}) = 1900$

{Because September 1 to January 1 is 4 months and the monthly simple interest rate is $\frac{3}{12}$ %}

⇒ 1.01x = 1900

⇒ x = $1881.19 (Rounded to the nearest cents)

Therefore, the student has to earn $(1900 + 1881.19) = $3781.19 (Answer)

8 0

3 years ago

What is the solution to the system of equations?

Dovator [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}$

$\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}$

$x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10$

4 0

3 years ago

Need more help on my homework<br> So I can get a better grade at school

Pie

Step-by-step explanation:

I'll help if you'd like

3 0

3 years ago

Can someone help me ​

Can someone help me