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gladu [14]
4 years ago
11

Please answer correct answer now fast

Mathematics
1 answer:
RideAnS [48]4 years ago
3 0

Answer:

Approximately 13.9 units.

Step-by-step explanation:

First, note that ΔTVW is a right triangle.

Since we are given that ∠UTV is 112°, this means that ∠WTV is 68° because 180-112 is 68°.

Now that we know ∠WTV is 68°, we can use the basic trigonometric ratios to solve for VW. VW is the side opposite ∠WTV. We also know the hypotenuse. So, we would use sine. Recall that:

\sin(\theta)=opp/hyp

Plug in 68° for theta, VW for the opposite, and 15 for the hypotenuse:

\sin(68)=VW/15\\VW=15\sin(68)\\VW\approx13.9078\approx13.9

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Answer:

B. The rate of change are the same, but the u-intercept are different

Step-by-step explanation:

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2 years ago
A loan of $1,020 was repaid at the end of 18 months with a check for $1,050. What annual rate of interest was charged?
marishachu [46]
We'll be assuming this is with simple interest.

now, a year has 12 months, thus in 18 months there are 18/12 years.

\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1050\\
P=\textit{original amount deposited}\to& \$1020\\
r=rate\to r\%\to \frac{r}{100}\\
t=years\to \frac{18}{12}\to &\frac{3}{2}
\end{cases}

\bf 1050=1020\left[ 1+r\left( \frac{3}{2} \right) \right]\implies \cfrac{1050}{1020}=1+r\left( \frac{3}{2} \right) \implies \cfrac{35}{34}=1+r\left( \frac{3}{2} \right)
\\\\\\
\cfrac{35}{34}-1=\cfrac{3}{2}r\implies \cfrac{1}{34}=\cfrac{3}{2}r\implies \cfrac{2\cdot 1}{3\cdot 34}=r\implies \cfrac{1}{51}=r
\\\\\\
r\%=100\cdot \cfrac{1}{51}\implies r\approx\stackrel{\%}{1.96078431372549}
8 0
4 years ago
Find the value of<br> a if 3x+ay=6​
Akimi4 [234]
I guess =ay=6-3x= ay/y=6-3x/y= a=6-3x/y
6 0
3 years ago
Read 2 more answers
Can someone please help me ?
VLD [36.1K]

The first one. 5x+7=12

7 0
4 years ago
Two vertical posts stand side by side. One post is 8 feet tall and the other is 17 feet tall. If a 24 foot wire is stretched bet
lianna [129]

Answer:

The distance between the posts is 3\sqrt{55} feet.

Step-by-step explanation:

In the attached figure, let DB and AC be the posts and let AD be the wire attached to the top of the posts.

BC is the distance between the posts and we need to find BC.

Note that BC = DE

Also, EC = DB = 8m and AE = AC - EC = 17 - 8 = 9 m.

Now, in the right triangle ADE,

AD^{2} =AE^{2} +DE^{2}

24^{2} =9^{2} +DE^{2}

DE^{2} =24^{2} -9^{2}

= (24+9) (24-9)

= 33(15)

= (3 × 11) × (3 × 5)

DE=3\sqrt{55}

Since DE = BC,

BC=3\sqrt{55}

Hence, the distance between the posts is 3\sqrt{55} feet.



7 0
3 years ago
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