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irina [24]
3 years ago
7

Why is b ≠ 1 a condition for f(x) = ab^x?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0
<h2>Explanation:</h2><h2></h2>

In this case, we hace the following exponential function:

f(x)=ab^x

Where:

a:Initial \ value \\ \\ b:the \ base

The base b\neq 1 because 1 raised to any power leads the result of 1. That is:

1^2=1 \\ \\ 1^3=1 \\ \\ 1^{\sqrt{3}}=1 \\ \\ \\ In \ conclusion: \\ \\ 1^{n}=1, \ \text{n any real number}

If so, then we won't get an exponential function, but a constant function:

f(x)=a

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2) We need to find natural number that is divisible by three primes. And it needs to be smallest possible. This means that the product of these numbers is our solution.
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4 years ago
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