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4 years ago

PLEASE I need this fast

Mathematics

1 answer:

Tatiana [17]4 years ago

8 0

I love the word of GOD so much that I agree with jwgirly the answer to the question is true.                                         1
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Factor 2x^2+7x-49<br><br> ( sorry that its 10 points i dont have many :/ )

Elza [17]

$2x^2+7x-49=2x^2+14x-7x-49\\\\=2x(x+7)-7(x+7)\\\\=\boxed{(x+7)(2x-7)}$

4 0

3 years ago

Read 2 more answers

Help pleeeaase

Vedmedyk [2.9K]

C. (2,3) The solution to the system of equations is where the two lines will intersect. looking at the graph that point is closest to C. (2,3)

6 0

4 years ago

Read 2 more answers

Paaaa hellllpppp po with solution po sana

ira [324]

<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

If something is being added to x, subtract it from both sides.
If something is being subtracted from x, add it on both sides.
Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

$5x+7=15$

Because 7 is being added to x, subtract it from both sides:

$5x+7-7=15-7\\5x=8$

Because x is being multiplied by 5, divide both sides by 5:

$\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}$

Therefore. $x=\dfrac{8}{5}$ .

<h3>Question 2</h3>

$7x+4=5x-18$

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

$7x+4-5x=5x-18-5x\\2x+4=-18$

To isolate x, subtract 4 from both sides:

$2x+4-4=-18-4\\2x=-22$

Divide both sides by 2:

$\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11$

Therefore, $x=-11$ .

6 0

2 years ago

Best answer will get brainliest

Naddik [55]

Step-by-step explanation:

uhm sorry its to blurd!! i will answer some other question

4 0

3 years ago

A biologist recorded a count of 337 bacteria present in a culture after 5 minutes and 699 bacteria present after 15 minutes.

hoa [83]

The initial population was 234.

<em><u>Explanation</u></em>

<u>Formula for the exponential growth</u> is: $A= P*e^r^t$ , where P is the initial amount, A is the final amount, r is the rate of growth and t is the time duration.