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IceJOKER [234]
3 years ago
6

Does anyone know where I can find answer keys for CPM Core Connections Course 3 (the eighth grade one) answers? Specifically for

Chapter 8? TYSM IF YOU CAN HELP ME
Mathematics
2 answers:
jasenka [17]3 years ago
7 0

Answer:

Yes of course! Now hurry and copy this link cause they will probably take this question down for putting it in. I hope that this helps!

Step-by-step explanation:

https://fliphtml5.com/itej/wqzy/basic/51-100

irina1246 [14]3 years ago
5 0

Answer:

copy and paste this

homework.cpm.org/category/CC/textbook/cc3

Step-by-step explanation:

hope this helps, it also has chapter 8.

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Which inequality is true?
alexdok [17]

9514 1404 393

Answer:

  А. Зп > 9

Step-by-step explanation:

The inequality of A may or may not be true. (It is true only if n > 3.) All of the others are definitely false.

3 0
3 years ago
Find the values of x and y.<br> 2(5x- 5)°<br> (5y + 5)º (7y - 9°<br> (6x + 50)
Amanda [17]

The values of x and y are 15 and 7 respectively

The angles formed from the intersection of two lines at X are equal and vertically opposite angles.

From the figure shown, we can conclude that:

2(5x-5) = 6x + 50 (vertically opposite angle)

Expand

10x - 10 = 6x + 50

10x - 6x = 50 + 10

4x = 60

x = 60/4

x =15

Similarly;

5y + 5 = 7y - 9

Collect the like terms;

5y - 7y = -9 - 5

-2y = -14

y = 14/2

y = 7

Hence the values of x and y are 15 and 7 respectively

Learn more here: brainly.com/question/15198257

4 0
2 years ago
A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t
Tomtit [17]

Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × \frac{1.2}{2}=0.6\,\,m (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3

4 0
3 years ago
Read 2 more answers
Mr. Mutler posts his students' artwork on a bulletin board.
Jlenok [28]
The length could be 5 and width 3. That would equal 15
8 0
3 years ago
How do you do this? Please help
PtichkaEL [24]

Answer:

PO=86.2\\ OM=23.8\\

Step-by-step explanation:

To preface, your figure is going to be a line segment, with O as your midpoint, in between points P & M.

With that being said:

PO+OM=PM

Identify your values:

PO=7y+12\\OM=3y-8\\PM=110

Substitute the values into the first equation:

7y+12+3y-8=110

Combine like terms:

10y+4=110

Subtract 4 from both sides of the equation:

10y=106

Divide by the coefficient of y, which is 10:

y=10.6

Substitute 10.6 for y in segments PO & OM:

PO=7(10.6)+12

OM=3(10.6)-8

PO=74.2+12

OM=31.8-8

Solve:

PO=86.2

OM=23.8

Check your answers by substituting:

PO+OM=PM

86.2+23.8=110

8 0
3 years ago
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