The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
Mean = 70,000 dollars
SD = 800 dollars
For Khan Academy
Step-by-step explanation:
Remark
I'm going to interpret this equation as
D = ut + kt² The only difference is the 2.
Solution
Subtract kt² from both sides.
D - kt² = ut Now divide by u on both sides.
The t's cancel out. on the right. You are left with u on the right.
The answer is 7. You can look at it like this. The two triangles are similar and the larger one's sides are twice the size of the smaller one's. So then we know GF is twice the size of JK.
2(2y+5)=5y+3
4y+10=5y+3
y=7
Answer:
dang with what
Step-by-step explanation:
