102 for 4th graders
197 for 7th graders
95 pages between 4th and 7th graders
Differentiate using the chain rule:
d/du [ln(u)] d/dx[2x^3+3x]
derivative of ln(u) = 1/u
1/u d/dx[2x^3+3x]
1/2x^3+3x d/dx[2x^3+3x]
Differentiate
(6x^2+3) 1/2x^3+3x
Simplify
Dy/dx = 3(2x^2+1) / x(2x^2 +3)
Answer:
I think its 1 baby because the 6 1/4 is 2 babies and the 8 1/2 is 3 babies so if you subtract 3 from 2 you get 1.
Usually, you're asked to model a situation with an equation. Here, you're given the equation and asked what situation it models.
The features of the equation that are of interest are ...
- multiplication of the unknown value by 17.35
- comparison of that product to 624.60, expecting the product to be greater than that value
The first two offered scenarios involve addition of an unknown value, not multiplication.
The third offered scenario compares a purchase price to a budget amount. Answering a question like this involves a "less than" comparison, not a "greater than" comparison.
The last offered scenario involves finding a variable value that will result in the product 17.35x exceeding 624.60—exactly what the given inequality models.
The appropriate choice is ...
... J Daren earns $17.35 ...