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Ksivusya [100]
3 years ago
11

The Quadratic equation y=0.5(x-1)(x-n) has an x - intercept at (1,0) and a vertex at (-2,4.5). what is the value of n A -5 B -2

C 2 D 5
Mathematics
1 answer:
andre [41]3 years ago
8 0

Step-by-step explanation:

the point being that a quadratic equation has 2 x-intercepts (or solutions of x for y = 0).

the advantage of this nice form the equation is written in is, that we see immediately both conditions, when y can be 0 : one of the bracket expressions must be 0.

so, the point (1, 0) covers (x-1).

we get the solution for (x-n), when we consider that such a quadratic function is simply a parabola and is symmetric around its vertex point.

the x value of the vertex (-2) tells us, that it is 3 units on the left side of the (1, 0) x-intercept point.

due to the symmetry of the curve the second x-intercept point must be even further to the left with additional 3 units distance in x direction.

so, -2 - 3 = -5

and A is the correct answer option.

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