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Mnenie [13.5K]
4 years ago
15

Like most cellular processes, transcription is directed by the action of -

Biology
1 answer:
podryga [215]4 years ago
7 0
The answer is A because the enzymes is the direct path way to the transcription.
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Suppose a nerve impulse must travel 0.90 m from your toe to your central nervous system. If the impulse travels at 150 m/s, calc
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<span>take the .9 meters it has to travel and multiply that by the 1 second it take to get 150 meters. Next all we have to do is take the product you get form that and divide it by the 150 meters. You should end up with 0.006 seconds to get 0.9 meters in the nervous system</span>
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Cell theory states that all living things contain one or more cells. Why do you think cell theory meets the definition of a scie
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Answer: yeah of course

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Which type of mutation results from the insertion or deletion of a nucletide into the gene?.
Artyom0805 [142]

​Frameshift Mutation

A frameshift mutation is a type of mutation involving the insertion or deletion of a nucleotide in which the number of deleted base pairs is not divisible by three. "Divisible by three" is important because the cell reads a gene in groups of three bases.

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5 0
2 years ago
In a population of 10,000 individuals of Monstera deliciosa, four individuals have a variegated phenotype that is caused by the
Mariulka [41]

Under the assumption of this population being in Hardy-Weinberg equilibrium,<em> the </em><em>probability</em><em> for the</em><em> fixation</em><em> of the var </em><em>recessive allele </em><em>equals 0.02 = 2%</em>

--------------------------------

<u />

<u>Available data:</u>

  • N = 10,000 individuals ⇒ Large population
  • 4 individuals have a variegated phenotype
  • variegated phenotype is caused by the recessive var allele
  • No selection, no additional mutation ⇒ we can assume Hardy-Weinberg equilibrium

We need to know the probability for the fixation of the var allele.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of variegated individuals in the population.

There are<u> 10,000 individuals</u>, and only <u>4 have variegated.</u>

So, the phenotypic frequency, F(Var) is 4/10,000 = 0.0004 =<u> 0.4%</u>

Since this is a recessive phenotype, this value equals the genotypic frequency, F(vv) = <u>0.4%</u>

Finally, we can get the allelic frequency by taking the square root of this value.

F(vv) = q² = 0.0004

f(v) = q = √0.0004 = 0.02 = <u>2%</u>

According to these calcs, the probability for the fixation of the var allele is <u>2%</u>, and the probability that all individuals express the variegated phenotype is <u>0.4%</u>.

------------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

brainly.com/question/9870841?referrer=searchResults

brainly.com/question/419732?referrer=searchResults

brainly.com/question/13603001?referrer=searchResults

brainly.com/question/5028378?referrer=searchResults

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3 years ago
The fish in the fish tank will run out of oxygen because
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If there are no plants in the tank, they will run out of oxygen because there is nothing producing oxygen.

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