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makkiz [27]
3 years ago
15

Can someone please answer. There is a picture. It is only one question. Thank you so much!

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0
Where is the picture ?
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If a cone has a height 6 feet and volume 54ft, find the radius of the base
OLga [1]

Answer:

The radius is approximately 2 93

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3 years ago
Helpppppppppppppppppppp pleaseeeeeeeeeee
Umnica [9.8K]

Answer:

FG = 16

Step-by-step explanation:

if df bisects <edg then  triangles DFE and DFG are similar AAA

since DF is the same in both triangles triangles DFE and DFG are congruent

therefore FE = FG

n+5 = 2n-6

subtract n from each side

n-n+5 = 2n-6-n

5 = n-6

add 6 to each side

5+6 = n

n=11

FG  = 2n-6

      =2*11 -6

    = 22-6

   = 16


6 0
3 years ago
Gavin goes to the market and buys one rectangle shaped board. The length of the board is 16 cm and width is 10 cm. if he wants t
Ira Lisetskai [31]
Check the picture below.

doesn't that make it just a 20 x 14?  well, surely you know what that area is.

8 0
3 years ago
PLEASE HELP DUE TODAY !
igor_vitrenko [27]

Answer:

let x be chips and y be sodas

8x + 4y = 5 ---> for the first hint

4x + 8y = 7------> second hint

0.25 cents is how much chips costs

and 0.75 cents is how much sodas costs

5 0
3 years ago
Read 2 more answers
From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
bulgar [2K]
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
=3(0.01)(0.9)
=0.027

(c) x &ge; 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
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