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3 years ago

SOMEONE HELP ASAP PLZZ

Mathematics

1 answer:

olga2289 [7]3 years ago

8 0

Answer:

$\frac{5\pm\sqrt{73}}{4}$

Step-by-step explanation:

The quadratic formula:

$\frac{-b+\sqrt{b^2-4ac}}{2a}$

So, we need to move all the terms to one side of the equation, which now becomes

$2x^2-5x-6=0$

Plugging in the numbers and you'll get the two roots/

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What is the inverse of the function??

Firlakuza [10]

$$\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
 \huge\underline{y=e^x-3}}
 \end{matrix}$
$

To get the inverse of any function f(x) [ just make sure that it passes the horizontal line test] follow the steps:

- Solve for x, i.e separate x in one side and the other terms in the other side, included f(x).

- Swap x and f(x).

- The result is the inverse of the original function $f^{-1}(x)$ .

-------------------------

Apply that on your function
$$\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
 \huge\underline{y=e^x-3}}
 \end{matrix}$
$

5 0

3 years ago

A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt

Katena32 [7]

Answer:

$2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}$

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be $y$ . The magnitude of $40\text{ m/s}$ will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is $60^{\circ}$ , we have:

$\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}$ (Recall that $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ )

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation $v_f^2=v_i^2+2a\Delta y$ to solve this problem, where $v_f/v_i$ is final and initial velocity, respectively, $a$ is acceleration, and $\Delta y$ is distance travelled. The only acceleration is acceleration due to gravity, which is approximately $9.8\:\mathrm{m/s^2}$ . However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

$v_i=20\sqrt{3}\text{ m/s}$
$a=-9.8\:\mathrm{m/s^2}$
$\Delta y =50\text{ m}$

Solving for $v_f$ :

$v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}$

3 0

3 years ago

PLEASE HELP 20 POINTS IF YOU HELP AND WILL BE MRAKED BRAINLEST!!!!!!!!!!!!!!!!The two-way table below shows the number of studen

Yuliya22 [10]

Your answer is the last option, 6.

We can work this out by looking for the total of people that like tennis in the table, and subtracting it from the total amount of people that like baseball.

This gives us a total of 46 people that like baseball, subtract 40 people that like tennis, and 46 - 40 = 6.

I hope this helps!

3 0

3 years ago

He short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inches

goldenfox [79]

The sum of two adjacent sides is 11 inches, so the long sides are 9 inches. The "unknown number" must be 12.

7 0

3 years ago

Please help me!!! Please? Ive been asking since yesterday<br> 8th grade math

suter [353]

I am pretty sure the answer is c. I hope this helps

4 0

3 years ago