Rhombus KLMN with vertices K(-3, 2), L(1, 4), M-1,0), and N(-5, -2): (x, y) → (x, y – 5) K'( L'(_. M' ( N' (.
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Yes, the partition gives the two brothers equal shares.
Step-by-step explanation:
Step 1:
Assume the entire field has an area of B. So one brother takes ,
, and
So we need to calculate how much this brother takes in terms of B.
To do this we calculate how much is.
Step 2:
To add ,
First take the LCM of the denominators 12, 6, and 4
The LCM is 12, we multiply the denominator to get the LCM value, this same value is multiplied to the numerator too.
Step 3:
One brother gets , so we need to calculate how much the other brother gets.
The other brother's share =
So both the brothers get equal shares