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Answer:
a) 3.5
b) 3.33
c) 
Step-by-step explanation:
As given,
A fair die is rolled 10 times
a)
Expected value of Sum of the number in 10 rolls = 
= 3.5
∴ we get
Expected value of Sum of the number in 10 rolls = 3.5
b)
Ley Y : number of multiples of 3
Y be Binomial
Y - B(n = 10, p =
)
Now,
Expected value = E(Y) = np = 10×
= 3.33
c)
Let m = total number of faces in a die
⇒m = 6
As die is roll 10 times
⇒n = 10
Now,
Let Y = number of different faces appears
Now,
Expected value, E(Y) = m - m
= 
Answer:
Option 1: 0.32
Step-by-step explanation:
Let
P(A) be the experimental probability of getting two
And
P(B) be the experimental probability of getting three
The dice is rolled 360 times.
So the sample space is n(S) = 360
P(A) = n(A)/n(S)
= 54/360
= 0.15
And
P(B) = n(B)/n(S)
= 62/360
= 0.172
As both the events A and B are mutually exclusive,
P(A or B) = P(A) + P(B)
= 0.15 + 0.172
=0.322
Rounding of to one decimal gives us:
0.32
So the probability of rolling a two or three is 0.32 ..
Answer:
A
Step-by-step explanation:
given
= 
using the method of cross- multiplication then
8P = 42 ( divide both sides by 8 )
P =
= 5.25