Answer:
KM=9
JK= 12.69
Angle JKM=45 degrees
ML=18.97
MKL=60 degrees
Angle L=30 degrees
Step-by-step explanation:
Triangle JKM is a 45, 45, 90 degree triangle so that means both side lengths are equal and the hypotenuse is square root of 2 times a side length. This means, KM will be equal to 9 and JK will be equal to 9 times square root of 2. For triangle KML, you know that the triangle is a 30,60,90 degree triangle. This means the hypotenuse is a^2+b^2=c^2 where c is the hypotenuse. Since you know that a is 9 and c is 21, plug them into the equation to get 81+b^2=441. Subtract 81 from both sides to isolate b^2 to get 360. b^2 = 360. Then find the square root of 360 which is about 18.97. Therefore, b or ML is equal to 18.97. Also, because we know that MKL is a 30, 60, 90 triangle, we know that angle MKL is equal to 60 degrees. Because we know the angles of MKL(60) and KML (90), we do 180-90-60 to find angle L. Simplify 180-90-60 to 30 and that means that angle L is equal to 30 degrees. Since we know that JKM is a 45, 45, 90 degree triangle, we know that JKM is equal to 45 degrees. Therefore, KM is equal to 9, JK is equal to 9 times square root of 2 or 9 times 1.41 which is 12.69. Angle JKM is 45 degrees, ML is 18.97, angle MKL is 60 degrees, and angle L is 30 degrees.
If this answer has helped you, please mark this answer as the brainliest
Given that <span>Line WX is congruent to Line XY and Line XZ bisects Angle WXY.
We prove that triangle WXZ is congruent to triangle YXZ as follows:
![\begin{tabular} {|c|c|} Statement&Reason\\[1ex] \overline{WX}\cong\overline{XY},\ \overline{XZ}\ bisects\ \angle WXY&Given\\ \angle WXY\cong\angle YXZ & Deifinition of an angle bisector\\ \overline{XZ}\cong\overline{ZX}&Refrexive Property of \cong\\ \triangle WXZ\cong\triangle YXZ&SAS \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AStatement%26Reason%5C%5C%5B1ex%5D%0A%5Coverline%7BWX%7D%5Ccong%5Coverline%7BXY%7D%2C%5C%20%5Coverline%7BXZ%7D%5C%20bisects%5C%20%5Cangle%20WXY%26Given%5C%5C%0A%5Cangle%20WXY%5Ccong%5Cangle%20YXZ%20%26%20Deifinition%20of%20an%20angle%20bisector%5C%5C%0A%5Coverline%7BXZ%7D%5Ccong%5Coverline%7BZX%7D%26Refrexive%20Property%20of%20%5Ccong%5C%5C%0A%5Ctriangle%20WXZ%5Ccong%5Ctriangle%20YXZ%26SAS%0A%5Cend%7Btabular%7D)
</span>
Answer:
t would be steeper
Step-by-step explanation:
A square's diagonal has a length equal to √(2) times the length of its sides. So if the side length is <em>x</em>, then the diagonal is such that
√(2) <em>x</em> = 10 cm
→ <em>x</em> = 10/√(2) cm ≈ 7.07 cm
The perimeter of a square is 4 times its side length, so the perimeter is
4 (10/√(2) cm) = 40/√(2) cm ≈ 28.3 cm
which makes 28.4 cm the closest answer.
Step-by-step explanation:
line 1 and 2 : parallel
as line 2 is actually
6x + 2y = 8
2y = -6x + 8
y = -3x + 4
so, they have the same slope (factor of x).
line 1 and 3 : neither
the slopes -3 and 3 are not parallel not perpendicular (90°).
line 2 and 3 : neither
as line 2 is parallel to line 1, it has the same relationship to line 3 as line 1.
