9514 1404 393
Answer:
500 ÷ 8 = 62 r 4, for example
Step-by-step explanation:
In order to have a remainder of 4, the divisor must be greater than 4, so could be any of 5, 6, 7, 8, 9.
The corresponding numbers could be any of ...
504 +5n . . . 0 ≤ n ≤ 19
502 +6n . . . 0 ≤ n ≤ 16
501 +7n . . . 0 ≤ n ≤ 14
500 +8n . . . 0 ≤ n ≤ 12
508 +9n . . . 0 ≤ n ≤ 10
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For example, with the divisor being 6, and n=13, the number could be ...
580 = 6·96 + 4
<h3>
Answer: -2w^2 + 25w = 25 or -2w^2 + 25w - 25 = 0</h3>
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Explanation:
Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.
The area of the rectangle is
Area = length*width
Area = L*W
Area = (25-2w)*w
Area = 25w - 2w^2
Area = -2w^2 + 25w
Set this equal to the desired area (25 square meters) to get
-2w^2 + 25w = 25
and we can subtract 25 from both sides to get everything on one side
-2w^2 + 25w - 25 = 0
side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)
a. By definition of conditional probability,
P(C | D) = P(C and D) / P(D) ==> P(C and D) = 0.3
b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.
c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.
d. Using the inclusion/exclusion principle, we have
P(C or D) = P(C) + P(D) - P(C and D) ==> P(C or D) = 0.6
e. Using the definition of conditional probability again, we have
P(D | C) = P(C and D) / P(C) ==> P(D | C) = 0.75
I think it might be r= -3