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melamori03 [73]
2 years ago
5

A plant breeder has determined the following variances for yield of corn in his fields:

Biology
1 answer:
Law Incorporation [45]2 years ago
6 0

Answer:

A. VG = 80

B. Broad sense heritability = 0.80

C. Narrow sense heritability = 0.30

D. Average yield = 430 Units

Explanation:

A. Given that

VA = 30

VD = 50

VI = assumed not available

Therefore

Total genetic variance (VG) = VA + VD

= 30 + 50

= 80

VG = 80

B. Given that

VP = 100

VG = 80

Broad sense heritability, H2 = VG/VP

= 80/100

= 0.80

C. Given that

VA = 30

VP = 100

Narrow sense heritability, h2 = VA/VP

=30/100

= 0.30

D. The difference in selection = 500 - 400

= 100

Recall,

Selection response is heritability multiplied by selection differential.

That is

R = h2S

Selection differential = 100

Heritability h2 = 0.30

Selection response = 0.30 × 100

= 30units

Therefore, expected average yield = 400 + 30

= 430 Units

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