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NISA [10]
4 years ago
8

How do you solve this

Mathematics
2 answers:
Andreas93 [3]4 years ago
4 0
This is the answer don’t be shy like it

yawa3891 [41]4 years ago
3 0

Answer:

(a).\:\:\int _1^{-1}3f\left(x\right)dx\:=-12   is the final answer.

Step-by-step explanation:

See the attachment below.

Best Regards!

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B) What is the measure of ∠E? Explain how you know. (1 point)
noname [10]

Answer:

I'm about 3 months haha, but I'll still help you out. Angle E is equal to 75 degrees.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
3 years ago
What is the answer to this inequality?<br> (x+7)&gt;80
Crank

Answer:

x > 73

Step-by-step explanation:

x+7 > 80

subtract 7 from both sides

x + 7 - 7 > 80 - 7

x > 73

-Chetan K

5 0
3 years ago
Help me please solve the circled question show your work
Rasek [7]

<u>Part 1)</u> Use the fact that there are 12 inches in a foot

a) How many inches tall is a 7 foot basketball player?

we know that

1 foot=12 inches

so by proportion

\frac{12}{1} \frac{inches}{foot} =\frac{x}{7} \frac{inches}{feet} \\ \\x=12*7\\ \\x=84\ inches

therefore

<u>the answer Part 1a) is</u>

84\ inches

Part b) If a yard is a 3 feet long, how many inches are in a yard?

we know that

1 yard=3 feet

1 foot=12 inches

so

Convert 3 feet to inches

by proportion

\frac{12}{1} \frac{inches}{foot} =\frac{x}{3} \frac{inches}{feet} \\ \\x=12*3\\ \\x=36\ inches    

therefore

<u>the answer Part 1b) is</u>

36\ inches

<u>Part 2) </u>At the farmer's market two pounds of peaches cost $4.20 How much will five pounds cost?

by proportion

\frac{4.20}{2} \frac{\$}{pounds} =\frac{x}{5} \frac{\$}{pounds} \\ \\2*x=4.2*5\\ \\x=4.2*5/2=\$10.5    

therefore

<u>the answer Part 2) is</u>

\$10.5

<u>Part 3) </u>Janice mother gave her a ten dollars bill to buy five pounds each of bananas and apples at the grocery store. When she got there she found that bananas were 80 c per pound and apples were $1.40 per pound.

Did Janice's mother give her enough money? If so, should she receive any change? If not, how much more money does she need?

 we know that

<u>Find the cost of the bananas</u>

5\ pounds*0.80\frac{\$}{pounds}=\$4

<u>Find the cost of the apples</u>

5\ pounds*1.40\frac{\$}{pounds}=\$7

Sum the cost of the bananas and the cost of the apples

\$4+\$7=\$11

\$11 > \$10------> Janice's mother didn't give her enough money

She needs more money

She needs-------> \$11-\$10=\$1

therefore

<u>the answer part 3) is</u>

She needs  \$1 more


3 0
3 years ago
Can someone please explain to me how to do this.
JulijaS [17]
Y = x² - 4x + 4
y = 2x - 4

Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

</span>&#10;\text {Length of AB}=  \sqrt{(4-0)^2 + (4-2)^2} =  \sqrt{16 + 4} = \sqrt{20}  = 4.47 \text{ units}
<span>
Answer: 4.47 units

</span>
4 0
4 years ago
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