Question

Hey can you please help me posted picture of question

Answer 1

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
$x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\ x= \frac{11+-1}{4} \\ \\ x=3, x= 2.5$

So, the correct answer to this question are option B and D