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3 years ago

Hey can you please help me posted picture of question

Mathematics

1 answer:

Debora [2.8K]3 years ago

4 0

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
$x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\ 
x= \frac{11+-1}{4} \\ \\ 
x=3, x= 2.5$

So, the correct answer to this question are option B and D

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3 years ago

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finlep [7]

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3 years ago

If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Fed [463]

Answer:

$\bold{(f+g)(x)=2x^2+\frac32x-5}$

Step-by-step explanation:

$f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5$

5 0

3 years ago

Figure A has a radius of 2 inches. It is dilated by a scale factor of 4 to form figure B. What is the radius of figure B?

snow_lady [41]

Given that figure A with radius of 2 inches is dilated to form figure B, the radius of B will be given by:
Radius B=(radius A)×(scale factor)
but
scale factor=4
thus
Radius of B will be:
2×4
=8 inches

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3 years ago

A projectile is fired straight up from ground level with an initial velocity of 112 ft/s. Its height, h, above the ground after

PtichkaEL [24]

Answer:

Step-by-step explanation:

We can do this the easy way and just set up an inequality and let the factoring do the work for us. The inequality will look like this:

$-16t^2+112t>192$ We will move the constant over and get

$-16t^2+112t-192>0$ and when you factor this you get that

3 < t < 4

Between 3 and 4 seconds is where the projectile reaches a height higher than 192 feet. With a little more work and some calculus you can find the max height to be 196 feet.

5 0

3 years ago