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Len [333]
4 years ago
12

Hey can you please help me posted picture of question

Mathematics
1 answer:
Debora [2.8K]4 years ago
4 0
We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\  \\ 
x= \frac{11+-1}{4} \\  \\ 
x=3, x= 2.5

So, the correct answer to this question are option B and D
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How many times does the digit 6 appear in the list of all integers from 1 to 100?
amm1812
20 times I think.
6,16,26,36,46,56,60,61,62,63,64,65,66,67,68,69,76,86, and 96
5 0
4 years ago
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Select the correct product <br> (x2+4) (x2-4)<br><br> x4 16<br> x4+16<br> x2+8x+16<br> x2 8x 16
natka813 [3]
The answer would be x^4 -16
Explanation: use the FOIL method.
(x^2 +4)(x^2 -4)= x^4 +4x -4x -16. 4x and -4x cancel each other out. You are left with x^4 -16.
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3 years ago
9, 14, 12,17,15, 20,18<br> what is the rule for the following pattern?
lidiya [134]
Add 5 then subtract 2 on the next number
3 0
3 years ago
There are 26.2 miles in a marathon. write the number of miles using a fraction
mash [69]
To make it easier say the number out loud. 26.2. Twenty six and two tenths. You could also say twenty six point two but the first way to say it makes it easier to write on paper though.

Twenty six and two tenths can also be reduced to twenty six and one fifth.

7 0
3 years ago
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
Pavel [41]

Answer:

The critical numbers/values are x = 0, 4/7, 2

Step-by-step explanation:

This is a doozy; no wonder you have it up here for help!

The critical numbers of a function are found where the derivative of the function is equal to 0.  To find these numbers, you have to factor the deriative or simply solve it for 0.  This one is especially difficult since it involves rational exponents that have to be factored.  But this is fun, so let's get to it.

First off, I am assuming that the function is

f(x)=x^{\frac{4}{5}}*(x-2)^2 which involves using the product rule to find the derivative.

That derivative is

f'(x)=x^{\frac{4}{5}}*2(x-2)+\frac{4}{5}x^{-\frac{1}{5}}(x-2)^2 which simplifies down to

f'(x)=x^{\frac{4}{5}}(2x^{\frac{5}{5}}-4)+\frac{4}{5}x^{-\frac{1}{5}}(x^{\frac{10}{5}}-4x^{\frac{5}{5}}+4) and

f'(x)=2x^{\frac{9}{5}}-4x^{\frac{4}{5}}+\frac{4}{5}x^{\frac{9}{5}}-\frac{16}{5}x^{\frac{4}{5}}+\frac{16}{5}x^{-\frac{1}{5}}

Let's get everything over the common denominator of 5 so we can easily add and subtract like terms:

f'(x)=\frac{10}{5}x^{\frac{9}{5}}-\frac{20}{5}x^{\frac{4}{5}}+\frac{4}{5}x^{\frac{9}{5}}-\frac{16}{5}x^{\frac{4}{5}}+\frac{16}{5}x^{-\frac{1}{5}}

Combining like terms gives us

f'(x)=\frac{14}{5}x^{\frac{9}{5}}-\frac{36}{5}x^{\frac{4}{5}}+\frac{16}{5}x^{-\frac{1}{5}}

This, however, factors so it is easier to solve for x.  First we will set this equal to 0, then we will factor out

\frac{2}{5}x^{-\frac{1}{5}}:

0=\frac{2}{5}x^{-\frac{1}{5}}(7x^2-18x+8)

By the Zero Product Property, one of those terms has to equal 0 for the whole product to equal 0.  So

\frac{2}{5}x^{-\frac{1}{5}}=0 when x = 0

And

7x^2-18x+8=0 when x = 2 and x = 4/7

Those are the critical numbers/values for that function.  This indicates where there is a max value or a min value.

5 0
3 years ago
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