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Yuri [45]
3 years ago
14

a grocery store display has 2 boxes of cereal on the top row,3 boxes in the next row,4 boxes in the next row, and so on. How man

y rows are there in the display if there are 44 boxes in all

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0
There ya go! The answer is 8 rows. Added a picture to show you my work :)

MatroZZZ [7]3 years ago
4 0
There would be 8 rows 
2+3+4+5+6+7+8+9 = 44

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A tree farm is building a greenhouse. Use the diagram to find the volume of the<br> greenhouse
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Step-by-step explanation:

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3 years ago
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A hot air balloon rose from a height of 100 m to 400 m in 3 minutes. What was the balloon’s rate of change?
maria [59]

Answer:

1.666666667 meter per sec^2

Step-by-step explanation:

I feel like this is physic

using acceleration formla Vf-Vi/t

so 400-100/180sec

300/180

1.666666667 meter per sec^2

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7 0
3 years ago
How much greater was Maiami’s annual rainfall than Albany’s Albany 46.92 miami61.05
Ilia_Sergeevich [38]

Answer:

52.94

Step-by-step explanation:

61.06

-46.92

=52.94

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5 0
3 years ago
You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
2 years ago
You have a kite whose diagnoals are 8 m and 22 m. Find the area of the kite. Show all of your work.
Wittaler [7]
-----------------------------
Formula
-----------------------------
\text {Area of a kite = }  \dfrac{pq}{2}  \text { where p and q are the diagonals }

-----------------------------
Find Area
-----------------------------

\text {Area = }  \dfrac{8 \times 22}{2}

\text {Area = }  \dfrac{176}{2}

\text {Area = } 88 \  m^{2}

-----------------------------
Answer: Area = 88m²
-----------------------------
6 0
3 years ago
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