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tamaranim1 [39]

3 years ago

6

the area of an equilateral triangle plot of land is 43.3sq m .if the land has to be enclosed by a galvanized wire 5 times ,how l

ong wire is required?

1 answer:

faltersainse [42]3 years ago

7 0

Answer:

1500

Step-by-step explanation:

You might be interested in

Solve the formula for the variable y: 5x+2y=10

Inessa05 [86]

The process is to go step-by-step to isolate the y.

To do this, you basically run the order of operations in reverse.

In 5x+2y=10, the first thing to move away from the left side is 5x and you cancel it out by subtracting 5x from both sides:

5x+2y - 5x = 10 - 5x

The 5x's on the left cancel leaving you with:

2y = 10 - 5x

Side note: this is more commonly written as 2y = -5x+10, since we tend to write variable terms first.

Finally, to get the y fully by itself, you need to cancel the 2 that's multplied against it. To cancel multiplication, you need to divide:

$\dfrac{2y}{2} = \dfrac{-5x+10}{2}$

The most important thing to remember here is that the 2 needs to divide into both terms on the right:

$\dfrac{2y}{2} = \dfrac{-5x}{2}+ \dfrac{10}{2}$

Finally, we simplify this into:

$y = -\dfrac{5}{2}x+5$

5 0

3 years ago

Plzzz Solve these 7 Questions ASAP !!<br> PLZZZZZZZZZZZ IT'S A REQUEST !!!

e-lub [12.9K]

Answer:

B is an answer.

6 0

4 years ago

I need help with how to reason it

artcher [175]

Answer:

X=80

Step-by-step explanation:

As 100⁰ is Opposite to B and AD and EH Are PARALLEL so B=100⁰

180-100

=80⁰

<h2>MARK ME BRAINLIEST </h2>

4 0

2 years ago

A = 4 0 0 1 3 0 −2 3 −1 Find the characteristic polynomial for the matrix A. (Write your answer in terms of λ.) Find the real ei

Illusion [34]

Answer:

Step-by-step explanation:

We are given the matrix

$A = \left[\begin{matrix}4&0&0 \\ 1&3&0 \\-2&3&-1 \end{matrix}\right]$

a) To find the characteristic polynomial we calculate $\text{det}(A-\lambda I)=0$ where I is the identity matrix of appropiate size. in this case the characteristic polynomial is

$\left|\begin{matrix}4-\lambda&0&0 \\ 1&3-\lambda&0 \\-2&3&-1-\lambda \end{matrix}\right|=0$

Since this matrix is upper triangular, its determinant is the multiplication of the diagonal entries, that is

$(4-\lambda)(3-\lambda)(-1-\lambda)=(\lambda-4)(\lambda-3)(\lambda+1)=0$

which is the characteristic polynomial of A.

b) To find the eigenvalues of A, we find the roots of the characteristic polynomials. In this case they are $\lambda=4,3,-1$

c) To find the base associated to the eigenvalue lambda, we replace the value of lambda in the expression $A-\lambda I$ and solve the system $(A-\lambda I)x =0$ by finding a base for its solution space. We will show this process for one value of lambda and give the solution for the other cases.

Consider $\lambda = 4$ . We get the matrix

$\left[\begin{matrix}0&0&0 \\ 1&-1&0 \\-2&3&-5 \end{matrix}\right]$

The second line gives us the equation x-y =0. Which implies that x=y. The third line gives us the equation -2x+3y-5z=0. Since x=y, it becomes y-5z =0. This implies that y = 5z. So, combining this equations, the solution of the homogeneus system is given by

$(x,y,z) = (5z,5z,z) = z(5,5,1)$

So, the base for this eigenspace is the vector (5,5,1).

If $\lambda = 3$ then the base is (0,4,3) and if $\lambda = -1$ then the base is (0,0,1)

3 0

3 years ago

a line has the equation 4y=3x-8 which is the equation of a line parallel to this line that has a y intercpt of 4?

Nikolay [14]

Answer:

y=34x+2.625

y=34x+2.75

y=−34x+1.25

y=34x+1.25

y=−34x+2.75

Correct answer:

y=−34x+2.75

Step-by-step explanation:

5 0

3 years ago