Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer:
1.1.1- Michael has 200 lovebirds in total
1.1.2- There are 40 birds in each cage
1.1.3- 120/80 = 3/2
Step-by-step explanation:
120+80=200
200÷5=40
120÷40=3, 80÷40=2
Answer:
Step-by-step explanation: dont work sorry
Answer:
14
Step-by-step explanation:
3 diangonalss joined togeheter is call a symertry
Answer:
24.9 repeating in
Step-by-step explanation:
![\sqrt[3]{15,625}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15%2C625%7D)
= 24.9 repeating.
Basically, just find the cube root of 15,625. Since, the object is a cube, the volume formula is V=
. Just undo the by finding the cube root. Hope this helps!!
