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yanalaym [24]
3 years ago
10

What is the inverse of the function? f(x) = 1/3x-5

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

        -1

       f   (x) = -3(x + 5)

Step-by-step explanation:

1)  in f(x) = 1/3x-5, replace f(x)= with y= as follows:  y = (1/3)x - 5

2) interchange x and y, obtaining:  x = (1/3)y - 5

3) solve this result for y:  (1/3)y = -x - 5, or -(x + 5).  Next, multiply both sides by                        3 to eliminate the fraction (1/3):  y = -3(x + 5)

4)  replace y with the symbol for "inverse of f(x);

        -1

       f   (x) = -3(x + 5)

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What is the ratio for the surface areas of the rectangular prisms shown below, given that they are similar and that the ratio of
Harrizon [31]

Answer:

9 : 1

Step-by-step explanation:

given a linear ratio = a : b, then the corresponding area ratio is

a² : b²

Here the linear ratio of their edges = 3 : 1, hence

ratio of surface areas = 3² : 1² = 9 : 1


4 0
3 years ago
What is 35.6 × 10−4 in standard form?
Fittoniya [83]

35.6\times10^{-4}=35.6\times0.0001=0.00356


a^{-n}=\dfrac{1}{a^n}\\\\10^{-4}=\dfrac{1}{10^4}=\dfrac{1}{10000}=0.0001

8 0
2 years ago
Which is a simplified form of the following expression? 6c^2+2.5d - d + 2c^2-3d
melisa1 [442]
By collecting like terms we have:

6 {c}^{2}  + 2 {c}^{2}  + 2.5d - d  - 3d \\  \\ 8 {c}^{2}  - 1.5d
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Four bags of rice and two bags of corn weigh 52 lbs. Three of the bags of rice weigh 24 lbs. What is the ratio of weight of the
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2.1666666

Step-by-step explanation:

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4 0
2 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
2 years ago
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