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scoundrel [369]
2 years ago
10

What is y=3x-14 in standard form

Mathematics
2 answers:
shtirl [24]2 years ago
7 0
the\ standard\ form:\ Ax+By=C\\\\y=3x-14\ \ \ \Rightarrow\ \ \ -3x+y=-14\ \ \ oder\ \ \ 3x-y=14
Dafna1 [17]2 years ago
4 0
The\ standard\ form:Ax+By=C\\\\=================\\\\y=3x-14\\\\3x-14=y\ \ \ \ \ \ |add\ 14\ to\ both\ sides\\\\3x=y+14\ \ \ \ \ \ |subtract\ y\ from\ both\ sides\\\\3x-y=14
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A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
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3 years ago
Which number(s) below belong to the solution set of the equation? Check all that apply.x + 12 = 13A.14B.1C.13D.312E.0F.25
Darya [45]
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3 years ago
2m^2 - 4m/ 2(m - 2) simplified
egoroff_w [7]

Answer:

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leva [86]

Step-by-step explanation:

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A square is inscribed in a circle of diameter 12 millimeters. What is the area of the shaded region? A square is inscribed in a
bezimeni [28]

Answer:  A. (72π - 144) mm²

<u>Step-by-step explanation:</u>

A_{shaded}=A_{circle}-A_{square}\\\\\\A_{circle}=\pi \cdot r^2\\.\qquad \ =\pi \bigg(\dfrac{12\sqrt2}{2}\bigg)^2\\\\.\qquad \ =\pi (6\sqrt2)^2\\.\qquad \ =72\pi\\\\\\A_{square}=side^2\\.\qquad \quad =\dfrac{12\sqrt2}{\sqrt2}^2\\\\.\qquad \quad =12^2\\\\.\qquad \quad =144\\\\\\\large\boxed{A_{shaded}=72\pi-144}

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3 years ago
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