Since 3 x 3 = 9, 9 is divisible by 3. So, 3 would be a factor of any number divisible by 9
To combine these terms you would add up the a's and b's.
4a+b+a is the same as 4a+a+b. Anything without a constant in front has a value of 1. You have 4a's and you need to add another a. That equals 5a's. The b is left alone since you can only add like variables.
The answer would be C) 5a +b
(-5C^2)^3-(5c)^6
-125C^5 - 15625c^6
Hey there!
<u><em>Your answer is </em></u>
<u>Here are the steps to solve:</u>
<em>Given:</em>
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<em>Distribute negative sign:</em>
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<em>Add like terms:</em>
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Have a great day! Hope it helped!
Answer:
4!
Step-by-step explanation:
In word MAXIMUM, consonants are M & X. According to the question itself, consonants should not occur together.
So, we have to put vowels at each even position; only then the condition will be satisfied.
We can put this in 3! ways (permutations of A, I & U).
For odd positions we can put 3-M's & a X. Total ways is 4!/3! (as repetitions of M).
Hence, the answer is 4!/3! x 3! = 24 ways.
24=4!.
