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andriy [413]
3 years ago
15

Jeanine paid an annual premium of $1,200 in total liability coverage for her car, including up to $400,000 in bodily injury cove

rage and $100,000 in property damage coverage. Twelve years into her policy, Jeanine caused an accident that resulted in the other driver claiming $40,000 in medical costs and $15,000 in car damage. Jeanine's insurance company paid the claim. Did the cost of the benefit of transferring the risk to the insurance company outweigh the cost of the premium? a.Yes, the cost of the annual premium for 12 years was more than the accident claims b.Yes, the cost of the annual premium for 12 years was less than the accident claims c.No, the cost of the annual premium for 12 years was the same as the accident claims d.No, the cost of the annual premium for 12 years was more than the accident claims
Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

The answer is B- Yes, the cost of the annual premium for 12 years was less than the accident claims.

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A parallelogram is shown below:
Marina CMI [18]
<h3>Answer:</h3>

A:  6 ft²

B:  3 ft² is the area of each of the two congruent triangles

<h3>Step-by-step explanation:</h3>

Part A. As with a rectangle, the area of a parallelogram is the product of base length and height.

  Area = (8 ft)·(3/4 ft) = 6 ft²

___

Part B. If you cut the area into two halves, each half will have half the area of the original. (That should not be a surprise.)

  triangle area = (6 ft²)/2 = 3 ft²

If the triangles are created by a diagonal across the original figure, each will have a base length and height that is the same as that of the original figure. The area of a triangle is half the product of base and height, so each triangle will have area ...

  triangle area = (1/2)bh = (1/2)(8 ft)(3/4 ft) = 3 ft²

5 0
2 years ago
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Which function has an inverse that is also a function? {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)} {(–4, 6), (–2, 2), (–1, 6)
DaniilM [7]
(-4,4) because its at the same hold for the other functions
4 0
2 years ago
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Please help ASAP IM IN DESPREATE NEED OF HELP
Advocard [28]

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality -y \le -2x-3.  You can make this easier to work with by multiplying through by -1.  Remember to switch the inequality sign when multiplying by a <u>negative</u> number.  OK, you get the inequality

y \ge 2x+3.

The graph will be a half-plane -- all the points on one side of a line.  The line that is the boundary of the half-plane has an equation:  y=2x+3 -- just use an  =  sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form:  y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1).  Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5).  Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality y \ge 2x+3 is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the <u>other</u> side!)

An easy point to pick in this case is the origin, (0, 0).  Put zeros in for x and y in the inequality, and you'll get the statement 0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3.  That's <u>false</u>, so shade the side of the line <u>not</u> containing the origin.  In the image below, the shading is in purple.

All right, now for the other inequality, x+2\le 0.  Subtract 2 from both sides and the inequality becomes x \le -2.  This, too, graphs as a half-plane whose boundary line has equation x=-2.  Graph the line.  A line with an equation that has  x  in it but not  y is a vertical line with all its x-coordinates equal to the number on the right side of the equation.  This line is vertical and goes through points such as (-2, 0).

Pick a point <u>not</u> on the line (the origin works again).  Put the coordinates into the inequality to get 0\le -2 which is <u>false</u>.  Shade the side of the vertical line which does <u>not</u> contain the origin.  In the image below, the shading is in black.

Finally,  YAY!  \o/ ,  the solutions to the system are all the points in the plane that got shaded twice.  In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities x \ge 0 and y \ge 0 in it.  These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis <u>and</u> to the right of the y-axis.

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3 years ago
Answer in slope intercept form (y = Mx + b)
denpristay [2]
The answer is y= 1x + 12

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Which equation can be used to find what percent 14 is of 125?
IgorC [24]

Answer:

B. 14 = 125p

Step-by-step explanation:

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