Answer:
Yes, the triangles are congruent by ASA
Step-by-step explanation:
we know that
If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)
In this problem
LK=MJ
∠KLJ=∠KMJ
∠LKJ=∠MJK
so
Two angles and the included side is equal in triangle JKL and triangle KJM
therefore
JKL≅KJM ----> by ASA
Answer:
x:-4,-3,-2,-1,0,1
f(x):-10,0,0,-4,-6,0
from the table we can see when x=0, y=-6
Therefore the y-intercept will be (0,-6)
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Answer:
25
Step-by-step explanation:
If HI and IJ are both the same and meet at the same point, the triangles would be the same.
Answer:
1. x = -4y ---> y = (-1/4)x
slope = -1/4. y-intercept = (0,0)
2. y = -2x + 4
3. y = (1/3)x - 1
Step-by-step explanation:
1. Re-write your equation so that x is on the right and y is on the left:
x = -4y ---> y = (-1/4)x
slope = -1/4. y-intercept = (0,0)
2. y-intercept = (0,4) ----> P1
x-intercrpt = (2,0) ----> P2
slope m = (y2 - y1) / (x2 - x1)
= (0 - 4)/(2 - 0)
= -2
therefore, y - y1 = mx - x1 ---> y - 4 = -2x
or y = -2x + 4
3. y-intercept = (0,-1)
x-intercept = (3,0)
m = (0 - (-1)) / (3 -0) = 1/3
y - (-1) = (1/3)x - 0 ---> y = (1/3)x - 1
-0.15 is the correct answer I suppose!
