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Dimas [21]
3 years ago
6

Which ordered pair is the solution to y − x = 3 and 2x + y = 9?

Mathematics
1 answer:
Cloud [144]3 years ago
5 0
Y-x=3
2x+y=9

so solving by multiplying first by 2
so we get , 2y-2x=6

adding both eqn now,

3y=15
y=5

so x=2

so y=5 and x=2 !!
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ab

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If you were to add 5 to my number and then divide by 4, you would get 7
Norma-Jean [14]
Let's make an equation. T will be the number.
(T+5)/4=7
Let's multiply both sides by 4 to get T by itself.
T+5=28
Subtract 5 from both sides.
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Your number is 23.
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the length is 8cm???

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n social studies class, Cole is making a scale drawing of a flag. The flag measures 24 inches high by 36 inches wide, having thr
Ray Of Light [21]
The complete question in the attached figures

we know that

1 ft---------------> 0.083333 in

so
<span>24 inches high--------------> 24*0.083333=2 ft
</span><span>36 inches wide--------------> 36*0.083333=3 ft

</span><span>we will analyze each drawing
</span><span>
drawing a) scale 1/4 in/ 1 ft ----------> (1/4)/1=1/4
for a high of 2 ft-------------> 2*(1/4)=0.5 in
f</span>or a wide of 3 ft-------------> 3*(1/4)=0.75 in
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drawing b) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing b) is not solution

drawing c) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
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drawing d) scale 1 in/ 1 ft ----------> (1)/1=1
for a high of 2 ft-------------> 2*(1)=2 in
for a wide of 3 ft-------------> 3*(1)=3 in
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the answer is 
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8 0
3 years ago
Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

  • 91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

  • 79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

Q1 = \frac{14}{4}th

Q1 = 3.5th

This is the average of the 3rd and the 4th element

Q1 = \frac{1}{2} \times (84 + 91)

Q1 = 87.5

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

Q3 =  3 \times 3.5th

Q3 =  10.5th

This is the average of the 10th and the 11th element.

Q_3 =\frac12 \times (98 + 101)

Q_3 =99.5

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

IQR = Q_3 -Q_1

IQR = 99.5 - 87.5

IQR = 12

Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0
2 years ago
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